Question

What is the value of Kp at 298 K for the reaction C4H6+ 1/2CH3OH 1/2 CO +C4H8given the following equilibrium data at 298K? (Note all reactions are in the gas phase. Hint: can you manipulate the reactions given below algebraically and add them together to obtain the reaction given above? How then should the Kp s of the reactions below be manipulated?) CH3OH CO + 2H2, Kp = 4.02 x 10-5C4H8 C4H6 + H2, Kp = 0.242

Answer 1

For the reaction, 0 CH + Ź CHOH Ž Ž co + P find out. 4 6 (g) 3 (9) Given that kp = Prico) PC Hz) (P= partial pressure) PCC GHG) P²CHOH) @ CHOH ECO+ 24, ; Kp = 4.02x10 © 643,- Se to do Kp = 0.242 kp = 4.028105 - P (col. Pån where P = partial pressure PeyOH) KP2 = 0.242= P(eh) Prz) Plealt Maltiply kp by Take square root of kp, to (kpi)" = (4.02x105) ?? _ ple coj. Prz) Divide plz (CHOH) Maltopily (KP,) by kpe; we get (pyk402x1039) - praco. Po KP2 0.242 . P/CHOH) /PGH) PHL) = (40.2x109??– 6. 34 x10% 0.0262 0.242 0.0262 = Plzco Pit) & Pleate = Plzco) PC HB) = 1kp P² CHOH) KAH ) PCCH PREHoH) kp = 0.0262 = 2.62x10² Pealty 0.242