Question

6. If the wavelength of the light emitted from a fiame test was measured to be 530 nm, no much energy did the electron releas
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Answer #1

We know that energy E= he X z wavelength LF - (6626X1634 JS) (39108 mei b = planck us constant 1mm = 109m (5363169 m) = 3.70*

Please check the calculations and pay attention to the unit analysis

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