When 1 mole of complete acetone burn it produces 5074kj of heat(negative sign indicate the heat flows out)
So when .5 mole acetone burned produce heat will be (5074÷2)=2537kj.
The balanced chemical equation for the oxygen combustion of acetone, C3H.O(l), the active ingredient in nail...
Consider the thermochemical equation for the combustion of acetone (C3H6O), the main ingredient in nail polish remover. C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g)ΔH∘rxn=−1658kJ If a bottle of nail polish remover contains 143 mL of acetone, how much heat is released by its complete combustion? The density of acetone is 0.788 g/mL.
Consider the following thermochemical equation for the combustion of acetone (C3H6O), the main ingredient in nail polish remover. C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g)ΔH∘rxn=−1790kJ If a bottle of nail polish remover contains 174 mL of acetone, how much heat would be released by its complete combustion? The density of acetone is 0.788 g/mL.
Consider the following equation for the combustion of acetone (C3H6O)(C3H6O), the main ingredient in nail polish remover. C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g)C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g) ΔHrxn=−1790kJ If a bottle of nail polish remover contains 154 gg of acetone, how much heat would be released by its complete combustion?
Consider the following thermochemical equation for the combustion of acetone, C3H6O, the main ingredient in nail polish remover: C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g) ΔH∘rxn=−1790kJ If a bottle of nail polish remover contains 173 mL of acetone, how much heat would be released by its complete combustion? The density of acetone is 0.788 g/mL. Express your answer in kilojoules.
2025 Consider the following themochemical equation for the corbution of acetone (C,H,O), the main ingredient in na polish remover C104) + 4 0 (g) + 30 (9) + 3H00 9) AH-1790 kJ Part A a bottle of nail polish remover contain 178 ml of acetone, how much hat would be released by its complete combustion? The density of acetone is 0788 / mL AH- Subm Provide Feedback Nex
1. What mass of natural gas (CH4) must you burn to emit 260 kJ of heat? CH4(g)+2O2(g)→CO2(g)+2H2O(g) ΔH∘rxn=−802.3kJ 2.Consider the following thermochemical equation for the combustion of acetone, C3H6OC3H6O, the main ingredient in nail polish remover: C3H6O(l)+4O2(g)→3CO2(g)+3H2O(g)ΔH∘rxn=−1790kJ If a bottle of nail polish remover contains 173 mL of acetone, how much heat would be released by its complete combustion? The density of acetone is 0.788 g/mL 3.Zinc metal reacts with hydrochloric acid according to the following balanced equation: Zn(s)+2HCl(aq)→ZnCl2(aq)+H2(g) When...
The balanced equation for the combustion of ethanol into carbon dioxide and water is found below.. C2H5OH (l) + 3 O2 (g) ----> 2 CO2 (g) + 3 H2O (l) a.calculate how many moles of oxygen gas are contained in 659 ml sample of oxygen at 1.07 atm and 21 degrees celcius b. a glass of wine contains 9.33g of ethanol. how many moles of oxygen would be needed to burn the ethanol contained in one glass of wine c....
e In Canvas D Question 3 2 pts Complete combustion of 1 mole of acetone (C3H&O) liberates 1790 kJ. Which of the following equations (with their correct AH° values) would not need to be used in any form to determine the enthalpy of formation of acetone? O C(graphite) + O2(g) CO2(8) ○ 3CO2(g) + 3H20(I) → 402(g) + C3H6O(1) O C(graphite) + 1/202(8) CO(g) ○ 2H2(g) + O2(g)-→ 2H2O(l) Next 4 Previous
I do not understand #5 1) Write the balanced chemical equation for the combustion of hexane, including physical states. Combustion reactions occur during burning, releasing heat and generally accompanied by light. Because of the heat, water will be produced as a vapor. 2 C6 H14 (g) + 19 02cg) 12 CO2 (g) + 14 H2O (9) Use the balanced chemical equation above and stoichiometry to solve the following problems. 2) Calculate the maximum number of moles of carbon dioxide that...
The combustion of propane (C3Hg) is given by the balanced chemical equation C3 Hg +502 + 3C02 + 4H2O How many grams of oxygen gas (O2) is needed in this combustion to produce 290 g of of carbon dioxide (CO2)? Round your answer to the nearest gram.