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2. Compare the bonding in F,?, F, and F. Include Lewis structures, molecular orbital structures, bond lengths and bond streng
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Answer #1

from the picture the Mo diagram of F2++, F2+ and F2 gives the bond order of 2, 1.5 and 1 respectively and since we know that the bond order is inversely proportional to the bond length. so the bond length of F2++ greater than F2+ and F2+ bond length is greater than the F2.

while looking at the MO diagram of NO and CN we can see there is one single electron present in the the antibonding Mo of NO and that can be easily removed compared to the CN, So the free redical gas phase reaction is more favorable in the first reaction.

I refer you to the image attached to this questionApy N N 1. IP 22 1 2 2 2p 2p - 25 1 0h25 : 1 2 1 ele 025 Bo (8) = 6 6-4 1 For ht: 016² 815² 825 825² oz po da +22 12P2 X2 stNo, mo diagram. 12 .Azpy 02s²2 12 025²825²8282 azpur **284 na 1 dep? Kapy 28. CN, mo diagram 825² *2.52 A2P op 2 KPN 1 A2 Py?

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