Mass of KNO3 in 1st solution = 6.00 % of 50.0 g
= 6.00*50.0/100
= 3.00 g
Mass of KNO3 in 2nd solution = 10.00 % of 100.0 g
= 10.0*100/100
= 10.0 g
Total mass of KNO3 in mixture = 3.00 g + 10.00 g
= 13.00 g
Total mass of solution = 50.0 g + 100 g
= 150 g
Use:
Mass % of KNO3 = mass of KNO3 * 100 / mass of solution
= 13.00 * 100 / 150
= 8.67 %
Answer: a
19. 50.0 g of a 6.00% m/m KNO3 in water solution are mixed with 100. g...
Cumulative/Challenge Probtems 18. If a 50.0 mL sample of 6.00 M KNO, solution is diluted to 2.00 L, what volume of this new solution would contain 25.0 g KNO,?
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PLEASE SHOW WORK!
A 50.0 mL sample of a 1.00 M solution of CuSO4 is mixed with 50.0 mL of 2.00 M KOH in a calorimeter. The temperature of both solutions was 20.3°C before mixing and 31.7 °C after mixing. The heat capacity of the calorimeter is 12.1 J/K. From these data, calculate AH for the process: CuSO4(1M) + 2KOH(2M) +Cu(OH)2 (s) + K2SO4(0.5M) Assume that the specific heat and density of the solution after mixing are the same as those of pure...
the date you need is: 2.0 grams of KNO3, the temp was
22.1.
extra information that might help if you need it: I added 5 mL
of water to the 2.0 g of KNO3.
please answer the 3 parts of the question. Thanks.
Grams KNO,Cryst. Temp, °c 22.1 2.0 g Type your calculation for solubility (in grams KNO,/100 grams water) using the data for the 2.0 gram sample. Type your calculation for molality of KNO, (in mol KNO3/kg water) using...
50.0 g of water at 22 °C is mixed with 125 g of water initially at 36 °C. What is the final temperature of the water after mixing, assuming no heat is lost to the surroundings?