Question

l CatOJ2WIll Feact completely with 5.00 moles of H3PO4? Part III: A gram to gram conversion- hint: this should use three conversion factors. First though, always check to make sure the equation is balanced! 2 C4H10 +13 02-8 CO2 +10 H20 How many grams of CO2 result from the complete combustion of 505 grams of butane (C4H10)?

Did i do this correctly? a little unorganized.

Answer 1

Geiven, balanced eaution, + 10 t0 24H10 + 1302 - [12 x ) +x10)2 butane (H1o) here, moleeular man 58 2mol 5 05 4 H10 butane (4 H1o) mol *. 505 2vam 58 mol 871 the Yeaution we know frem 8 moles 4ct 7vom 2 mole we C2 meler 4 x 871 mele t1o tem 871 2 moles af c2 34 84 (16 X2)] 2/m [(12x) Molar mes + 44 3/me 34.84 X mele 2 34-84 1532.96 쉬 Ca2 27 Ca2 23 (1533 Co, uil be released Henee, 1533