part 1
Na2C2O4 is salt of strong base ( NaOH) and weak acid (NaHC2O4) .
given concentration of salt (Csalt) = 0.35 M
hence,
pH = 7 + ( pKa2 + logCsalt )
pH = 7 + ( pKa2 + log 0.35)
or, 8.87 = 7 + ( pKa2 - 0.456)
or, pKa2 - 0.456 = 2 × (8.87 - 7)
or, pKa2 - 0.456 = 3.74
or, pKa2 = 3.74 + 0.456 = 4.196.
hence Ka2 of oxalic acid = 10-4.196 = 6.36×10-5
so,
part 2
given , Kb = 7.4×10-7 , hence,
pKb = - logKb = - log (7.4×10-7) = 6.13
pH = 10.72
for weak base
pH =14 - ( pKb - logC)
or, 10.72 = 14 - ( 6.13 - log C)
or, - (6.13 - logC) = (10.72 - 14)
or, - (6.13 - log C) = - (3.28×2)
or, log C - 6.13 = - 6.56
or, log C = (6.13 - 6.56)
or, log C = - 0.43
or, C = 10(-0.43)
or, C = 0.37 M.
concentration of nicotine = 0.37 M.
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