solution:-
given that mean = 15 ,standard deviation = 1.7
sample n = 13
degrees of freedom df = n - 1 = 13 - 1 = 12
critical T value = 3.055
Margin of error(E) = T * standard deviation/sqrt(n)
= 3.055*1.7/sqrt(13)
= 1.4404
confidence interval formula
mean +/- margin of error
15 +/- 1.4404
=> 13.5596 < µ < 16.4404
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