A survey of 25 randomly selected customers found that their average age was 31.84 years with...
A survey of 25 randomly selected customers found that their average age was 31.84 years with a standard deviation of 9.84 years.
- What would the critical value t* be for a 95% confidence
interval with 99 degrees of freedom?
- What would the margin of error be for a 95% confidence interval
for this data (with the sample size of 25)?
- Construct a 95% confidence interval for the mean age of all
customers for this data (with the sample size of 25) assuming that
all conditions and assumptions have been met for the confidence
interval.
- How would the confidence interval have changed if the standard
deviation of the 25 randomly selected customers was 15 instead of
9.84?
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A survey of 25 randomly selected customers found that their
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years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
A survey of 25 randomly selected customers found the ages shown? (in years). The mean is...
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A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.60 years and the standard deviation is 9.52 years a) Construct a 90% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.00 years and the standard deviation is 9.99 3 years. a Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions or the con interval have been met b) How large is the margin of error? c) How would the confidence interval change i you had assumed that the standard deviation was known to be 10.0...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is...
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33 46 48 21 30 32 10 31 20 29 A survey of 25 randomly selected customers found the ages shown (in years). The mean is 31.76 years and the standard deviation is 10.37 years. a) Construct a 98 % confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 20 38 40 35 40 interval have been met. 22 37 10 41 26 b) How large is the margin of error?...
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c) Also, would the confidence interval become more narrow, or
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years. A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.84 years and the standard deviation is 8.84 25 39 43 25 42p a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence 23 28 42 45 31 interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 33.60 years and the standard deviation is 9.52 years a) Construct a 90% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you had assumed that the standard deviation was known to be 10.0 years?...
A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.00 years and the standard deviation is 9.99 3 years. a Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions or the con interval have been met b) How large is the margin of error? c) How would the confidence interval change i you had assumed that the standard deviation was known to be 10.0...
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c) Also, would the confidence interval become more narrow, or
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A survey of 25 randomly selected customers found the ages shown (in years). The mean is 32.92 years and the standard deviation is 9.73 years a) Construct a 99% confidence interval for the mean age of all customers, assuming that the assumptions and conditions for the confidence interval have been met. b) How large is the margin of error? c) How would the confidence interval change if you...
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