a.
a.
Let the breakeven ROR be i%, then
EUAC of Design 1A = 2600000 * i + 325000
EUAC of design 1B = 3400000 * i + 40000
As per given condition
2600000 * i + 325000 = 3400000 * i + 40000
(3400000 - 2600000)* i = 325000 - 40000
800000 * i = 285000
i = 285000 / 800000 = 0.35625 ~ 35.63%
b. When MARR = 15%
EUAC of design 1A = 2600000 * 0.15 + 325000 = 715000
EUAC of design 1B = 3400000 * 0.15 + 40000 = 550000
As the EUAC of design 1B is lower, it should be selected
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