12. The ordered dose of potassium phosphate is 18mmol in 250ml of 0.9% NaCl
Available concentration of vial is 4mEq / ml = 3mmol
Means 1 ml of concentration has 3mmol
Then for 18mmol of concentration we should take 6 ml of the concentration
13. The ordered dose of amphotericin B is 0.25mg/kg
Weight of the patients is 154 lbs = 154 × 0.45
= 69.3 kg
So, ordered dose will be 0.25 × 69.3 = 17.3 mg
Available dose of amphotericin B is 50mg in 10ml
50 mg of amphotericin B is present in 10ml
1mg of amphotericin B will be present in 10/50
Then 17.3 mg of amphotericin B will be present in 10/50× 17.3
= 3.46 ml of available drug contains 17.3 mg of amphotericin B.
i need help answering questions 12,13,14 please 12. You receive an order for 18 mmol of...
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