How many grams of a 5% sulfur ointment must be mixed with 180 grams of 20% sulfur ointment to prepare an 8% sulfur ointment?
Answer: [a] g of 5% sulfur ointment (#g) Do not
round
Allegation is an arithmetical method of solving problems that involve the mixing of ingredients possessing different percentage strengths. In this method for calculating the quantity of a component of given strength that should be mixed with a specified quantity of another component of given strength to make a preparation of desired strength involves the following steps are required:
· First step is to find relative amount of individual components needed.
The difference between strength of stronger component (20 %) and desired strength (8%) indicates parts of weaker strength to be used.
So 20 - 8 = 12 parts parts of weaker strength
AND
The difference between the desired strength (8%) and the strength of the weaker component (5%) indicates the number of parts of the stronger strength to be used.
So 8 – 5 = 3 parts of stronger strength
Hence the relative amounts of both the strengths of sulphar ointment to be used are
= 3 parts stronger strength : 12 parts weaker strength
=1 : 4
· Second step is calculating required quantity using dilution formula
Dilution formula is
Quantity 1 X Concentration 1 = Quantity 2 X Concentration 2
That is Q1 * C1 = Q2 * C2
= Q1 / Q2 = C1 / C2
On putting values:
4 Parts/ 1 Part = X grams / 180
On cross multiplication
X = 4* 180 grams
= 720 grams
Hence 720 grams of 5 % sulphur ointment should be added to 180 grams of 20 % sulphur ointment to get ointment of final strength of 8%.
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