Part A A solid conducting sphere has net positive charge and radius R = 0.700 m...

Question

Question

Part A A solid conducting sphere has net positive charge and radius R = 0.700 m the center of the sphere, the electric potent

Answer 1

Answer #1

Given :

We are given a sphere with a positive charge q with radius R = 0.700 m

The potential due to this charge at distance r = 1.20m is V =18V .

We are asked to calculate the potential at the center of the sphere .

The potential energy due to sphere is given by equation :-

V = 1 / 4π€° q/r = V = 1/r

At 1.20 m,

V = 18

V = kQ/1.20 m

so at the surface,

V' = kQ / 0.700m

Dividing the two gives

V / V' = 18.0V / V' = 0.700m / 1.20m

and so

V' = 30.8 V

Answer 2

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