Question

sedber of leges ve bee uinginees to seh ts Ading toa dy from t yer. 3ef admsons effeers indcated that they vaed anlying sudents sec nekng page Aandm sample of 500 amissions oficers ws reenty selected and tw found that of them vist the socia ning s ofsiudents appying to ther oollege Using , omplete pars a and Does this sample provide suppo for the hypothess h the propon of admissions afficers whe vist an pplying stdents sooal networking page has inoesed in the past year Dmine the nl and ahmative hypothess Chocse the comect anaer below Mpa3 p0 p 3 p-034 p034 H 3 sta f e Deemine he oical 42 se a comma to separate an Raund so neo decimal places as needed) a neeed Calculate the test wtatiatic &1 Ran d mes neded Dmine the onolaion Choese the comect anwer belw ORejct H The is not suficent evidence uppon the hypothesis that the propartion of admasions officers who wiait an applying ude oc neoking page has inoased in the past year Do not rject H Thee a sufficent vidence to suppot the hypatheais that the proportion af admiaaions officers who viait an applying audenta ocal atworking page has inoeased in the past ye Donot ejet H Thee s not suffcent evidence to sport the hypothess that the propoon of admissions offficers whe vist an soplying students socal etwoking page has inoresed in the pst yer D Reject H Thee aufficent avidence to uppot the hypothesis that he proportion af admiasions officers who viat an applying audentswocal natworking page has inoeased in the past year b Deemine the pre for test evae Round places as eded)

Answer 1

Solution:-

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: P < 0.34
Alternative hypothesis: P > 0.34

Note that these hypotheses constitute a one-tailed test.

Formulate an analysis plan. For this analysis, the significance level is 0.01. The test method, shown in the next section, is a one-sample z-test.

Analyze sample data. Using sample data, we calculate the standard deviation (S.D) and compute the z-score test statistic (z).

S.D = sqrt[ P * ( 1 - P ) / n ]

S.D = 0.0211849
z = (p - P) / S.D

z = 0.19

where P is the hypothesized value of population proportion in the null hypothesis, p is the sample proportion, and n is the sample size.

z_Critical = + 2.327

Rejection region is z > 2.327.

Interpret results. Since the z-value (0.19) does not lies in the rejection region, hence we failed to reject the null hypothesis.

Do not reject H₀, there is not sufficient to support the hypothesis that the proportion of admissions officers who visit an applying students social networking page has increased in the past year.

b)

Since we have a one-tailed test, the P-value is the probability that the z-score is greater than 0.189.

Thus, the P-value = 0.425

Interpret results. Since the P-value (0.425) is greater than the significance level (0.01), hence we failed to reject the null hypothesis.