1. If the geometry is given we have to observe the loading conditions.
2. We have to find the stresses.
3. We have to find the maximum stress.
4. Since the and factor
of safety are given, we have to find the allowable stress by the
formula
/factor of
safety.
5. Now we have to compare the maximum stress with the allowable stress.
6. If maximum stress is less than or equal to the allowable stress, then the design is safe.
Internal force, stresses, allowable stress P 400 kN C L 3.75 m P2 720 kN B...
[Qe-Home/Lab -] From a swinging pendulum of m = 0.5Kg and length L = 0.6m (small angle approx.) complete the following tasks: (get it data from here, use speed data only) Qua) Compare the theoretical and observed pendulum's period (T) Qab) Estimate the maximum displacement angle. Show work. fx D E F B 1 2 3 4 5 6 7 8 9 10 11 12 Run #13 Run #13 Run #13 Run #13 Position (m) Velocity (m/s) Acceleration (Force (N)...
Question 3 A 10 m square and 7.5 m deep pit is to be excavated in a soil with a unit weight of 20 kN/m2. What is the stress relief at 2 m. 5 m and 10 m below the centre point of the bottom of the excavation? b. The circular flexible area is uniformly loaded (q 320 kN/m2). Determine the change in vertical stress: i. at point A At a point 2 m below point A 4 m A...