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6. The first ionization energy of Au (IE1) is 890.1 kJ/mol. Is light with a wavelength of 225 nm capable of ionizing a gold a
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Answer #1

6)

Energy from light = hc/wavelenth = 0.08 x 10 ^ -17

IE1 = 0.148 x 10 ^ -17

IE > Light from energy, so not capable of ionizing.

7)

The quotients of energy levels in any atom is always an integer. But 4.45/2.69 = 1.65 is not. So no such energy level.

Energy level = Re / n2

Re = 2.18 x 10 ^ -18 J => n = 7

8)

hc/wavelenth = (Z=12)x(Re ) / (1/n2 ) - (1/(n+1)2 )

Obtaining value of jumping from level 2 to level 3

9)

Apply the above formulae

But for calculation sake,

(a) The spectral line from level 2 to 5 in Hydrogen is 434nm. So in Li it'll be 434/Z = 434/3 = 144.66 nm = 1.4466 x 10-7 m

(b) 2.18 x 10-18 x 3 x 0.21 x 0.75 x 6.023 x 1023 = 0.62 MJ

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