Ans 6 :
E = hc/ lambda
h = 6.626 x 10-34 J.s
c = 3.0 x 108 m/s
Wavelength = 225 nm = 2.25 x 10-7 m
putting values:
E = ( 6.626 x 10-34 J.s x 3.0 x 108 m/s) / (2.25 × 10-7 m)
= 8.83 x 10-19 J or 8.83 x 10-22 KJ
for one mole :
= 8.83 x 10-22 x 6.022 x 1023 KJ/mol
= 532 KJ/mol
This is less than the ionization energy mentioned so this light is not capable to ionize gold atom.
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