Suppose that 10.00 mL of 0.0100 M IO3- solution requires 12.68 mL of the thiosulfate solution...
Suppose that 10.00 mL of 0.0100 M IO3- solution requires 12.68 mL of the thiosulfate solution to be standardized. What is the molarity of the thiosulfate solution? Answer with a number with no unit.
Homework Answers
2IO3^- (aq) + 6S2O3^2- (aq) + 6H^+ ----------> 3S4O7^2- (aq) + 2I^- (aq) + 3H2O(l)
2mole 6mole
IO3^- S2O3^-
M1 = 0.01M M2 =
V1 = 10ml V2 = 12.68ml
n1 = 2 n2 = 6
M1V1/n1 = M2V2/n2
M2 = M1V1n2/n1V2
= 0.01*10*6/(2*12.68)
= 0.024M
The molarity of thiosulfate = 0.024M
0.024>>>>answer
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