Question

Let's suppose a loop of wire has a square shape and each side has length S and the current is I. If the loop is in the yz-plane and the center is located at (0,0,0), what is the magnetic field due to the loop of wire at a location x lying on the x-axis? Give its magnitude.

I'm putting the answer below, but I would like to know how to get it. So, please explain your solution carefully and I'll rate it as soon as you post it.

S2 S x 4 277 x

Answer 1

X 13 = AB LBx=Bs0 X+ 2 Ab X S/2

Mashetse fied due t a 6= 4-エ( Sint Sin g) [ formule] Cu weat semet tragt 2 Direction of magnetic field can be found using right hand thumb rule. But in our case, line segment AB is the bisector line for ab, so, then, B S/2 3 2. + X 2万

From the Tt faure Horizon tal Ceupo heut of Verfil Compoheut of B BSino Since, there are four line segments, so, net magnetic field in the horizontal direction would be zero. because horizontal component of magnetic field due to opposite sides of the square is equal in magnitude but in opposite directions. now, net vertical component of magnetic field due to contribution of four wire 46 Siu het

4 (A 2 ナXと 2 S2 By net +x2 4 + 2