Question

Full-Wave Rectifier without filter.

Based on the above output waveform, calculate the DC component using equation (5.16) and the second harmonic of the output using equations (5.17) and (5.18) with h=2.

Full-Wave Rectifier with filter.

Calculate the corner frequency of the low pass filter to verify that it is much smaller than 120 Hz. Compare the DC output of the rectifier with the low pass filter and compare it to the earlier calculations.

Why does the full-wave rectifier output not contain first harmonic, which is more difficult to filter?

162 18H62 V1 RI 1000 45 Vrs }60 Hz D4 18H62 1862 Oscilloscope-XSC1 Tme 229.244m 229.244m 0.000 ChanneA 6173 .173 0.000 Chane Reverse Save recter r2-T Ext. gger Chane Scale Tmebase Chamel A Trigger AM Scale: 20maC so vD S VDve Scale: tdge t t 1H 18H62 D1) 18H62 100pF 45 Vrs 60 Hz 1000 D4 18H62 1862 Oscilloscope-SC Chamel Ohannel 373 370 Time 22.113 228.113 Reverse 0.000 0.000V Channel Tmebase Chamel A Trigger Scale 20m Scale 0 v Salev dge 44 AM

Answer 1

This question is based on full wave rectifier output waveform analysis.

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