Question

Problem 7 (15pts) Convert this following pseudo-code in high level language into a piece of an assembly code (NIOS 2). In the following pseudo-code in high level language, r4, r5, r6, and r10 represent registers 4,5, 6, and 10, respectively Consider this pseudo-code in high level language: If ! (r4 >r5 or rs <r6) r10=r10+1 else r10- r10-1 This becomes the following piece in assembly code (put you answers inside each parenthesis): ) #r2 is set to 1, if r4>r5; othe rwise, r2 is set to 0; ( ). r3 is set to 1, if r5cr6; otherwise, r3 is set to 0 ) # #put answer here ). #If (r4 > r5 or rs<r6), r2, ( we move to else label; ), else r10, r10, addi 1 else: subi r10, r10, 1

third photo is problem 8 pt 2. anything would help please

Answer 1

7)

S1 t r2 r4 r5

Sgt r3 r5 r6

and r2 r2 r3

bne r2 1 skip

add r10 r10 1

skip: sub r10 r10 1