Compute the correct CPU computations and actions.
Write the final updated values for each memory, register and flags after the given instruction executes in the space provided. There are multiple parts of this problem.
Endianness: Check for endianness in case of loads and stores, in each part of the question. If the question does not specify the endianness, you can assume little-endian.
A)
LDRSB R10,[R4,#0x18]! uses pre-indexed immediate addressing mode.
1. This instruction evaluate R4+0x18 first and update R4 since it is pre-indexed instruction. It increments the index prior to the use.
R4=R4+0x18=0x000084F0+0x18
=0x00008508
2. Read the lower byte of data from the memory address 0x00008508 ie C3
3. Load into register R10 with sign extended form. ie MSB(31-8) will be filled with 1. ie 0xFFFFFFC3
(C3 is 1100 0011 with sign bit 1 as highlighted and this will be extended till the 31st position ie
1111 1111 1111 1111 1111 1111 1110 0011=FFFFFFC3)
4. Flag N=1 since the sign of the number is 1
Register R4 and R10 and Flag N are modifiied here and all other memory and register contents remains the same.
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using ARM64 assembly language. this was all the information I was given, if unable to answer please refund question, please dont ask for additional information Compute the correct CPU computations and actions. Write the final updated values for each memory and register after the given instruction executes in the space provided. There are multiple parts of this problem. Check for endianness in case of loads and stores in each part of the question. (Note: Only write the changed values, if...