4. Consider the transfer function, Y(s)_ 3 F(s) + s(s2 + 2s + 4) (a) Qualitatively, what is the time response y(t) if f(t) represents a unit-step input? What is the value of y(t) when time is sufficiently large? What is the time constant that we may use to evaluate the "speed" of response? (b) Repeat step (a) if f(t) represents an impulse input. What is y(t) when time is sufficiently large?
Find the inverse Laplace transforms of (a) (b) (c) s 1 (2s +1) Y(s) = (822 5s + 8 (2s - 2) 21) Y(s) = Find the inverse Laplace transforms of (2s- 3)e-3,s 1) (2s (a) Y(s)2s+ ) (2s - 2) (c) Y(s) = (5-7)2 s 1 (2s +1) Y(s) = (822 5s + 8 (2s - 2) 21) Y(s) = Find the inverse Laplace transforms of (2s- 3)e-3,s 1) (2s (a) Y(s)2s+ ) (2s - 2) (c) Y(s) =...
= 0 and L{f} = (s2 + 2s +5)(s - 1) A function f(t) has the following properties: f Ps – 10 is an unknown constant. Determine the value of P and find the function f(t). 28 +5)(-1): Where P
Find the Laplace transforms of the following functions: a) F(s) = (25-1)(2s+1) (4s2–4s+1)2 S+1 bb F(s) = (s2–25+5)
Find the inverse Laplace transformation of: a) F(s)- b) F,(s)--2 c) F(s) = 2,242 4 s2+6s +5 s2 +3s +1 3+2s+s s2 +9s +18 e) F(s)--一5 2s4 +12s+90 (s+2)(s +2s+2)
Solve 2+2s+3 (s2 +2s+2)(s2 +2s+5)
with an angle of departure and arrivals Root -locus for following equations b)G24645) c) G(s)- 3s2+5s+1 s(s+2) (S+3) (s+4) (s2+2s+4) Root -locus for following equations b)G24645) c) G(s)- 3s2+5s+1 s(s+2) (S+3) (s+4) (s2+2s+4)
3. Use method of residues to calculate inverse Laplace Transform of the following: s4-2s+1 s2 (s2+4) s2-2s+1 a) X(s (b) X(s) = (s+2)2+4
usio Exercise 3 H(s)- (s2+1 (s2+2s +1) ( 42st)
Question 1- Plot the root loci for the closed-loop control systems with K s b) Gs)H(S)425+2 s2+2s+2 c) G (s)H(s) = K+22+2 K(s+2) K (s+6) K(s+18) K(s+4.5) = (s+5)(s2 +25+5) f) G (s)H(s) K (s2+3s+9) g) G (s)H(S)-(s+5)(s2+2s+s) h) G (s)H(s) = (s+5)(S2 + 25+5) i) G (s)H(s) = s(s+5)(s2+2s +5) Question 1- Plot the root loci for the closed-loop control systems with K s b) Gs)H(S)425+2 s2+2s+2 c) G (s)H(s) = K+22+2 K(s+2) K (s+6) K(s+18) K(s+4.5) = (s+5)(s2...