Translate the following queries into extended Relational Algebra (Use COUNT to do this one) Find every...
Translate the following query into extended Relational Algebra Find every person who is skilled at the manufacture of more products manufactured by company 111-22-3333 than the average number of the company’s products at which employees of the company are skilled company(co_name, govt id, ceo_ssn, hq_loc) division(co id, div name, subdiv_of, dir_ssn, div_hq) site(co id, divname, loc) product(prod id, manuf co, manuf_div, loc, prod_descr) person(ssn, name, address) works_for(ssn, co id, div_name, salary, emp_id, sup_ssn) skill(ssn, prod id, manuf co company(co_name, govt...
Consider following relational database schema and translate the queries ‘a’ and ‘b’ into relational algebra expressions Teacher(ID, Name, Designation, Phone, Address) Course(CourseCode, CourseName, CreditHour) Taught(TeacherID, CourseCode, Semester) a. SELECT Name, Address FROM Teacher, Taught WHERE Teacher.ID=Taught.TeacherID and CourseCode=’IT344’ b. SELECT CourseName FROM Course, Taught WHERE Course.CourseCode=Taught.CourseCode and TeacherID=200