1. The weight of athlete W = 70×9.81 = 686.7N
This weight is divided equally on both knees i.e. 686.7÷2=343.4N
Hence upward force produced by each knee=343N
2. When the athlete supports his entire weight on one leg, then the upward force produced by that knee =686.7N
3. When athlete take up, accelerate or jump his knees produce more upward force.
4. The static force of friction should be able to balance the total weight of athlete on one knee, and the maximum normal force on one knee is 686.7N hence the maximum static force of friction should be always less than 686.7 N
In-depth analyses A. We are going to think a lot about the knees of a 70-kg...
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