Question

IN JAVA. P0\/\/|\|3D. In the early 80s, hackers used to write in an obfuscated, but mostly readable way called “leet” – short for “elite”.  In essence, it was a simple character replacement algorithm, where a single “regular” character was replaced by one or more “leet” characters; numbers remained the same.  Here’s one of the most readable versions:

a	4	g	9	m	/\\/\\	s	$	y	‘/
b	B	h	|-|	n	|\\|	t	7	z	Z
c	(	i	1	o	0	u	U
d	D	j	j	p	P	v	\\/
e	3	k	|<	q	Q	w	\\/\\/
f	Ph	l	L	r	R	x	><

Note! You will need to know how to 1) get the length of a string (the number of characters) and 2) access individual characters of the string.  See the appendix for more information.  You must use at least one method in addition to main – preferably one that translates individual characters! In JAVA

Answer 1

Screenshot

tnter a teat for remui Flap Leet text of the given text is SLLDas import j.util.Seanner; public class LeetComversion public seati ation String et for ingut read aicn rintEnter a test for ronuersian: et Tength of the entered strir t trig to gete chsracter fort set Ste . coesp0ding leet code etu a code then add it into 1ttra berad se sa eharacter add into leet et+ text.chartt!1) /Dtsolay leet text the given text is "tleet) Systen.out.printin"Leet text methed to find lungth of the string
Program

//Import for input read
//Map for comparison
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;

public class LeetConversion {

   public static void main(String[] args) {
       //Variable for leet text generation
       String leet="";
       //Scanner object for input read
       Scanner sc=new Scanner(System.in);
       //Prompt for input teaxt for conversion
       System.out.print("Enter a test for conversion: ");
       String text=sc.nextLine();
       //Call method to get length of the entered string
       int len=StringLength(text);
       //Loop unti end of the string to gete character by character
       for(int i=0;i<len;i++) {
           //Call method to get correspoding leet code
           String str=getLeet(text.charAt(i));
           //If function return a code then add it into the leet
           if(str!=null) {
               leet+=str;
           }
           //Otherwise same character add into leet
           else {
               leet+=text.charAt(i);
           }
       }
       //Display leet text
       System.out.println("Leet text of the given text is "+leet);
      
   }
   //Method to find length of the string
   public static int StringLength(String text) {
       return text.length();
   }
   //Method to find the leet form of a character
   public static String getLeet(char ch) {
       //MAp for mapping character and leet expression
       Map<Character,String> leetComp=new HashMap<Character,String>();
       leetComp.put('a',"4");
       leetComp.put('b',"B");
       leetComp.put('c',"(");
       leetComp.put('d',"D");
       leetComp.put('e',"3");
       leetComp.put('f',"Ph");
       leetComp.put('g',"9");
       leetComp.put('h',"|-|");
       leetComp.put('i',"1");
       leetComp.put('j',"j");
       leetComp.put('k',"|<");
       leetComp.put('l',"L");
       leetComp.put('m',"?/\\/\\");
       leetComp.put('n',"|\\|");
       leetComp.put('o',"O");
       leetComp.put('p',"P");
       leetComp.put('q',"Q");
       leetComp.put('r',"R");
       leetComp.put('s',"$");
       leetComp.put('t',"7");
       leetComp.put('u',"U");
       leetComp.put('v',"\\/");
       leetComp.put('w',"\\/\\/");
       leetComp.put('x',"><");
       leetComp.put('y',"'/");
       leetComp.put('z',"Z");
       //Loop for comparison
       for(char key:leetComp.keySet()){
           if(key==ch) {
               return leetComp.get(key);
           }
       }
       return null;
   }

}

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Output

Enter a test for conversion: hello98
Leet text of the given text is |-|3LLO98

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Note:

I assume you need the program this way

If you have any doubt, let me know