Question

Normal and Frictional Forces Ranking Task

Six boxes held at rest against identical walls.
Rank the boxes on the basis of the magnitude of the normal force acting on them.

Rank from largest to smallest. To rank items as equivalent, overlap them.

140 N pushing on 5kg box against wall
140 N pushing on 3kg box against wall
120 N pushing on 3kg box against wall
150 N pushing on 7kg box against wall
130 N pushing on 7kg box against wall
150 N pushing on 1kg box against wall
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Answer #1

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From the above diagram,

The normal force (n) = Pushing force (F)

In this case normal force is independent of mass of box.

So the larger the pushing force have larger normal force.


Rank the boxes on the basis of the magnitude of the normal force acting on them(  largest to smallest ).

(150 N pushing on 7kg box against wall) =(150 N pushing on 1kg box against wall ) > (140 N pushing on 5kg box against wall)= (140 N pushing on 3kg box against wall) > (130 N pushing on 7kg box against wall)> (120 N pushing on 3kg box against wall).


answered by: physicswow
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