Type 1 | Type 2 | Type 3 | Total | |
Sum | 456.8 | 473.4 | 547.6 | 1477.8 |
Count | 8 | 8 | 8 | 24 |
Mean, Sum/n | 57.1 | 59.175 | 68.45 | |
Sum of square, Ʃ(xᵢ-x̅)² | 144.48 | 81.155 | 134.38 |
Number of treatment, k = 3
Total sample Size, N = 24
df(between) = k-1 = 2
df(within) = N-k = 21
df(total) = N-1 = 23
SS(between) = (Sum1)²/n1 + (Sum2)²/n2 + (Sum3)²/n3 - (Grand Sum)²/ N = 584.41
SS(within) = SS1 + SS2 + SS3 = 360.015
SS(total) = SS(between) + SS(within) = 944.425
MS(between) = SS(between)/df(between) = 292.205
MS(within) = SS(within)/df(within) = 17.1436
a) Null and Alternative Hypothesis:
Ho: µ1 = µ2 = µ3
H1: At least one mean is different.
F = MS(between)/MS(within) = 17.0446
p-value = F.DIST.RT(17.0446, 2, 21) = 0.0000
As p-value = 0.0000 < 0.01, we reject the null hypothesis.
ANOVA | |||||
Source of Variation | SS | df | MS | F | P-value |
Between Groups | 584.4100 | 2 | 292.2050 | 17.0446 | 0.0000 |
Within Groups | 360.0150 | 21 | 17.1436 | ||
Total | 944.4250 | 23 |
b) Assumptions:
c) Tukey's method:
Q statistic at α = 0.01, k = 3, N-k = 21, Q = 4.62
Samples in each treatment, n =8
Comparison | Absolute Diff. = |xi - xj| | Critical Range, CV = Q* √(MS(Within)/n) | Results |
µ1-µ2 | 2.075 | 6.7631 | Means are not different |
µ1-µ3 | 11.35 | 6.7631 | Means are different |
µ2-µ3 | 9.275 | 6.7631 | Means are different |
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