Question

its brr[8]

(40%) Convert the following C-pseudo code into MIPS assembly code as a standalone program (including main and all the required directives). You can use any register. You must comply, however, with the convention of register usage. Before writing your code perform an explicit register allocation phase. Note that the C snippet is int arr[8]; int brr[4]-{1, 2, 3, 4, 5, 6, 7, 8) int i-8; while (i>-0) arrli]-brr[i-); (40%) Convert the following C-pseudo code into MIPS assembly code as a standalone program (including main and all the required directives). You can use any register. You must comply, however, with the convention of register usage. Before writing your code perform an explicit register allocation phase. Note that the C snippet is int arr[8]; int brr[4]-{1, 2, 3, 4, 5, 6, 7, 8) int i-8; while (i>-0) arrli]-brr[i-);

Answer 1

Screenshot

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Program

#Data declaration part
.data
     arr: .word 0 0 0 0 0 0 0 0           #arr[8]
     brr: .word 1 2 3 4 5 6 7 8          #brr = {1,2,3,4,5,6,7,8}
#Program starts here
.text
#Main program
.globl main
main:
    #Get the base address of arr
    la $s0,arr
    #Get the base address of brr
    la $s1,brr
    #Initialize variable i=8
    addi $t0,$0,8
    #Address increment to get last
    addi $t1,$0,4
    mul $t1,$t1,$t0
    add $s0,$s0,$t1
    add $s1,$s1,$t1
#While loop i>=0
whileLoop:
     blt $t0,0,exitLoop
     #Get brr value into t1
     lw $t1,($s1)
     #store into arr, brr[i]=arr[i--]
     sw $t1,($s0)
     #decrement address
     addi $s0,$s0,-4
     addi $s1,$s1,-4
     #Decremnet i
     addi $t0,$t0,-1
     j whileLoop
#End of the program
exitLoop:
     addi $v0,$0,10
     syscall