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1.80-kg carton of milk at arms length (see the figure below). What force Fg must be exerted by the biceps muscle? (Ignore th

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Answer #1

Given that:

Torque provided by the carton mg times the total distance

Fc = mg * (0.25 + 0.08)

m= 1.80 kg

Fb = torque provided by biceps which is perpendicular force  times the radius

Fb = Fc

mg (0.25 + 0.08) = Fcos (theta) * 0.08

1.80 * 9.8 * 0.33 = F cos (75) * 0.08

5.8212 = F * 0.25 * 0.08

F = 291.06 N

note : image was not available so i copied the image address on google , so i m not sure about the numerial values ( i.e distances). But method used here is correct.

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