Question

10. + 0/2 points Previous Answers SerCP11 16.2.OP.013. My Notes The figure below shows three positively charged particles at three corners of a rectangle. The particle at upper left has a charge 4, = 8.00 nC, the one at the lower left has a charge of q, = 7.00 nC, and the one at lower right has a charge 4z = 3.00 nC. The rectangle's horizontal side has length x = 5.50 cm and its vertical side has length y = 2.50 cm. (a) What is the electric potential (in V) at the upper-right corner of the rectangle? (Assume the zero of electric potential is at infinity.) 3642.93 x What is the electric potential at a point due to a single charged particle? Given more than one charged particle, how do you find the total potential at a point? How far is each charge from upper right point? Be careful with units and signs. V (b) What would be the potential in V) at the upper-right corner if the charge q, at lower left was -7.00 nC instead?

Answer 1

Here 8=527+ gr 8= 15.587 (2.50 8 = 6.042cm = 6.042810m x = 5.5x12m, y = 2.50x15m from the point We know that the electric potential at & distance charge. V=K% So The net potential at point A V=K91 +K 2 + K93 - ① V=9x108x8x159 9x108x7x109 9x10 3 x 3 x 10 5.5X152 6.042x152 2.58102 Vm= 13.091x10 +10.427X10%+10.2 X102 Vo= 34.318X10" => [V, 3431-8 V) 2 7 6.042 X 152 102 2.58102 when 9 = ~ 7X1594. Then from eg. VA= 9x108x8x153 +9x10x (-7x158) 9x108x3x10² 5.5x102 VA= 13.091X102-10.427x10 +10-8X102 VA= 13.464x10² IVA = 1346.4v