Question

Consider the following reaction at 300 K: 2 AB (g) ↔   A2 (g) + B2 (g)...

Consider the following reaction at 300 K:

2 AB (g) ↔   A2 (g) + B2 (g)

In a particular experiment, the partial pressures of A2 and I2 at equilibrium are 0.715 and 0.573 atm, respectively, while the partial pressure of AB is 3.63 atm. What is the equilibrium constant for this reaction?

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Answer #1

2 AB - ALTB2 kp= [PAL] [ lg, [PADIL - (0.715 x 0.513) (3.63)2 10.0311

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