For the reaction 2 A(g) + 3 B(g) ↔ 2 C(g) + 2 D(g), the equilibrium...

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For the reaction 2 A(g) + 3 B(g) ↔ 2 C(g) + 2 D(g), the equilibrium...

For the reaction 2 A(g) + 3 B(g) ↔ 2 C(g) + 2 D(g), the equilibrium constant at 298 K is 1.409×10^-11. If the initial partial pressures of A, and B are 0.500 bar, and 0.718 bar, respectively, determine the partial pressure of D (in bar) once equilibrium has been reached at 298 K.

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Answer 1

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2A + B = 2042D Ka 1.409/10- initial 0.5 0.718 0 o final (0.5-22) (0.718-32 an zu k = P2 P² - (2x)² (22) Apr (0.5o2x) 2 (0.718

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