Given this reaction at equilibrium: N 2O 4 ↔ 2NO 2, calculate the equilibrium constant (K p) if the partial pressures of N 2O 4 and NO 2 are 0.0238 atm and 0.196 atm respectively.
A. |
1.61 |
|
B. |
8.24 |
|
C. |
0.00289 |
|
D. |
0.621 |
Answer is A.
Kp is the product of the concentration of products divided by the product of the concentration of reactant with each term raised to their coefficients as power.
Kp = [NO2]2/[N2O4]
= (0.196)2/(0.0238)
= 1.61
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