Question

e gy y eksion method - Acceleration of the freely falling object by graphical method Percentage error in 'g' = Laboratory Assignments 1. A boy threw a stone to his friend on the balcony. The stone stopped rising in 2.9 seconds. How high did the stone rise? [2 marks]

Answer 1

1) oy= Voyt & Layt? Vy = Voy rayt Given by = o(rest) ie stopped ay = -9,8 m/s? (ve because it is downwards) t = 2.95 o = Voy + (-9.8) X2.9 = Voy - 28.42 m/s by = Voyt + I qyt² = 28.42 x 2.9 +1x-918) x 2.92 = 141.2 m Voy = o crest) t = 2.6s ays -9.8 m/s2 Vy= Voy tayt - ot 79.8) x2.6 = -25.48 m/s magnitude = 25.48 = 125.5 m/s -ve because downwards Voy = 0 (rest) Vy = -147m/s Ay = -9.8 m/s2 Vy = Voy tayt -147= 0+ (-9.8)xt =) t = 15s