A man is standing 3.40 m in front of a convex spherical mirror of radius of curvature 4.20 m. How far is the image from the object?
Focal length of the convex mirror f=R/2 =4.20/2 =2.10 m
Using mirror equation
1/f =1/v+1/u 1/v=1/f -1/u ...1
Here f=2.10 m , u= -3.40 m ( I am using cartesian sign convention )
put these value in equation 1
1/v=1/2.10 +1/3.40
1/v= (3.40+2.1)/(2.10*3.40)
=5.50/7.14
v=7.14/5.50=1.298
v=1.30 m (distance of the image from the mirror )
the distance of the image from the object
d=v+3.40=1.30+3.40
d=4.70 m Answer
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