Question

A convex mirror has a radius of curvature of 46.7 cm

A convex mirror has a radius of curvature of 46.7 cm. A 11.5-cm-tall object is placed in front of the mirror and produces an image that is 5.13-cm tall.

(a) What is the magnification?

(b) How far is the object from the mirror?

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Answer #1

Radius of the convex mirror = R = -47.7 cm (Negative as it is a convex mirror)

Focal length of the convex mirror = f

f = R/2

f = -47.7/2 cm

f = -23.85 cm

Height of the object = ho = 10.2 cm

Height of the image = hi = 5.73 cm

Magnification of the image = M

M M = hi he

M = 5.73 10.2

M = 0.562

Distance of the object from the mirror = do

Distance of the image from the mirror = di

M M = di d.

0.562 d; do

d; = -0.562d,

By Mirror Equation,

f ºp + di

f de (-0.562d,

(1 f = de 0.562

do = f(1- 0.562

d, = (-23.85)(1 – 0.562

do = 18.6 cm

a) Magnification of the image = 0.562

b) Distance of the object from the mirror = 18.6 cm


answered by: ANURANJAN SARSAM
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