A convex mirror has a radius of curvature of 46.7 cm. A 11.5-cm-tall object is placed in front of the mirror and produces an image that is 5.13-cm tall.
(a) What is the magnification?
(b) How far is the object from the mirror?
Radius of the convex mirror = R = -47.7 cm (Negative as it is a convex mirror)
Focal length of the convex mirror = f
f = R/2
f = -47.7/2 cm
f = -23.85 cm
Height of the object = ho = 10.2 cm
Height of the image = hi = 5.73 cm
Magnification of the image = M
M = 0.562
Distance of the object from the mirror = do
Distance of the image from the mirror = di
By Mirror Equation,
do = 18.6 cm
a) Magnification of the image = 0.562
b) Distance of the object from the mirror = 18.6 cm
A convex mirror has a radius of curvature of 45.0 cm. A 10.7-cm-tall object is placed in front of the mirror and produces an image that is 5.95-cm tall. (a) What is the magnification? (b) How far is the object from the mirror? cm
A convex (diverging) mirror of radius of curvature 20 cm in magnitude, produces an image of an object placed at 15 cm from the mirror. Where is the image located from the mirror? How tall is the image if the object is 5 cm tall? What is the nature of the image?
The magnitude of the radius of curvature of a convex spherical mirror is 29.0 on. (Include the sign of the values in your answers) (a) What are the location and magnification of the image of an object placed 16 5 on in front of the mirror? location cm magnification Is this image upright or inverted? upright inverted (b) What are the location and magnification of the image of an object placed 59 5 on in front of the mirror? location...
2)A spherical mirror has a radius of curvature of 22 cm. if the mirror is convex, what its focal length is? 3)If light of wavelength 600nm in air enters a medium with index of refraction 1.5, what is the wavelength in this new medium? 4) A concave mirror with a focal length of 40 cm has 2 cm tall object placed 35 cm in front of it, the image formed is? A) real and inverted B) real and upright C)...
An object is placed in front of a convex mirror with a -25.0-cm radius of curvature. An upright image half the size of the object is formed. At what distance is the object from the mirror? Draw a ray diagram to illustrate.
The side-view mirror of an automobile has a radius of curvature of 11.5 cm. The mirror produces a virtual image one-third the size of the object. How far is the object from the mirror? cm
An object is 60.1 cm in front of a convex spherical mirror that has a radius of curvature of 68.2 cm. (a) What is the image distance? cm (b) What is the magnification? (c) Is the image upright or inverted?
The image behind a convex mirror (radius of curvature = 87.0 cm) is located 29.0 cm from the mirror. (a) Where is the object located (give the distance to the mirror) and (b) what is the magnification of the mirror?
A convex mirror has a radius of curvature that has a magnitude
equal to 24 cm.
(a) Use the mirror equation
1
s
+
1
s'
=
1
f
where f =
r
2
to calculate the image distances for the object distances
given.
s (cm)
s' (cm)
53
26
14
7.0
0.8
(b) Calculate the magnification for each given object distance.
s (cm)
m (cm)
53
26
14
7.0
0.8
Please help with parts A and B of this...
The magnitude of the radius of curvature of a concave spherical mirror is 34.0 cm. a. What are the location and magnification of the image of an object placed 60.0 cm in front of the mirror? Is this image real or virtual? Is it upright or inverted? b. What are the location and magnification of the image of an object placed 34.0 cm in front of the mirror? Is this image real or virtual? Is it upright or inverted?