Given:
Sof(NH4Cl(aq)) = 169.9 J/mol.K
Sof(NH3(g)) = 192.45 J/mol.K
Sof(HCl(aq)) = 56.5 J/mol.K
Balanced chemical equation is:
NH4Cl(aq) ---> NH3(g) + HCl(aq)
ΔSo rxn = 1*Sof(NH3(g)) + 1*Sof(HCl(aq)) - 1*Sof( NH4Cl(aq))
ΔSo rxn = 1*(192.45) + 1*(56.5) - 1*(169.9)
ΔSo rxn = 79.05 J/K
This is when 1 mol of NH4Cl reacts as per equation.
For 2.29 mol,
ΔSo rxn = 79.05 * 2.29
= 181 J/K
Answer: 181 J/K
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