1)
Given:
Sof(Ca(OH)2(aq)) = -74.5 J/mol.K
Sof(HCl(aq)) = 56.5 J/mol.K
Sof(CaCl2(s)) = 104.6 J/mol.K
Sof(H2O(l)) = 69.91 J/mol.K
Balanced chemical equation is:
Ca(OH)2(aq) + 2 HCl(aq) ---> CaCl2(s) + 2 H2O(l)
ΔSo rxn = 1*Sof(CaCl2(s)) + 2*Sof(H2O(l)) - 1*Sof( Ca(OH)2(aq)) - 2*Sof(HCl(aq))
ΔSo rxn = 1*(104.6) + 2*(69.91) - 1*(-74.5) - 2*(56.5)
ΔSo rxn = 205.92 J/K
This is when 2 moles of Ca(OH)2 reacts as per equation.
For 2.26 moles,
ΔSo rxn = 2.26 * 205.92 J/K = 465.4 J/K
Answer: 465.4 J/K
Only 1 question at a time please
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