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Score: 2 of 4 pts 3 of 3 (3 complete) v HW Score: 52%, 5.2 of 10 pts %) Problem B.29 Question Help Consider Paul Jordans fol

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Answer #1

a)

Graphical representation is following:

+ rn « -80 1x + 3y > 90 (3.75, 65) XX 8x + 2y > 160 -60 X 3x + 2y > 120 (8,48) y<65 M x + 5y = 90 (25.714, 21.429) -101 -20 -

Feasible region is the shaded region, which is bounded on one side by points as highlighted on the graph and unbounded towards infinity X1-axis

Value of objective function is minimum at point (90,0)

Therefore, optimal solution is:

X1 = 90

X2 = 0

Objective value = 1*90+5*0 = 90

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