Question

P1300 35° Length 797 d1 pivot d2 Length Art of rotation Axs of row Arir of 30 50 115 pivote 156 Length Length L lal (f) (e) T(b) In Figure (b) the length of the bar L = 1.60 m. What is the lever arm (in meters) for force F? Enter a number Submit (5 a(g) In Figure (g) the distance from the pivot to the upper end d1 = 0.50 m. What is the lever arm (in meters) for force F1? EIn Figure (g) the distance from the pivot to the lower end d2 = 0.60 m. What is the lever arm (in meters) for force F2? EnterIn order to make the NET Torque (by forces F1 and F2) = 0, what should be the magnitude (in Newtons) of force F2? Enter a numplease answer all parts to each question

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Answer #1

a)

r2 = lever arm length for F2 = d2 Sin90 = 1 Sin90 = 1 m

r1 = lever arm length for F1 = d1 Sin35 = 1 Sin35 = 0.57 m

b)

r = lever arm length for force F = L Sin50 = 1.60 Sin50 = 1.23 m

c)

r = lever arm length for force F = L Sin50 = 1.60 Sin50 = 1.23 m

d)

r = lever arm length for force F = L Sin(180 - 130) = 1.60 Sin50 = 1.23 m

e)

r = lever arm length for force F = L Sin(50) = 1.60 Sin50 = 1.23 m

f)

r = lever arm length for force F = L Sin(50) = 1.60 Sin50 = 1.23 m

g)

r1 = lever arm length for F1 = d1 Sin90 = 0.50 Sin90 = 0.50 m

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