Homework Answers
Given Kb of NH3 = 1.8x10-5
so pKb = -log 1.8x10-5 = 4.75
[base] = C = 0.461M
for a weak base
pOH = 1/2[ pKb -logC] = 1/2[4.75 -log 0.461]
= 2.543
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