A particle with a charge of q = -5.60 nC is moving in a uniform magnetic field of B⃗ =( -1.23 T ) k^. The magnetic force on the particle is measured to be F⃗ =( −7.60×10−7 N )j^.
Part B
Calculate vx, the x component of the velocity of the particle.
Express your answer in meters per second.
m/s
A particle with a charge of q = -5.60 nC is moving in a uniform magnetic...
A particle with charge − 5.60 nC is moving in a uniform magnetic field B⃗ =−( 1.26 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^. Calculate the scalar product v⃗ ⋅F⃗ .
A particle with charge − 5.40 nC is moving in a uniform magnetic field B⃗ =−( 1.28 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^. Part A Part complete Are there components of the velocity that are not determined by the measurement of the force? Are there components of the velocity that are not determined by the measurement of the force? yes no SubmitPrevious Answers Correct Part B...
A particle with a charge of q = -5.20 nC is moving in a uniform magnetic field of B with sole component B, = -1.28 T. The magnetic force on the particle is measured to be F with sole component Fy = -7.60x10-7 N Calculate Vz, the x component of the velocity of the particle. Express your answer in meters per second. View Available Hint(s) ΡπΙ ΑΣφ ? v_v_x = 144.2 m/s Submit Previous Answers X Incorrect; Try Again; 3...
A particle with charge - 5.00 nC is moving in a uniform magnetic field B=-(1.24 T ). The magnetic force on the particle is measured to be =-(3.80-10-7N)2+(7.60-10-7N)). Part B Calculate the 1-component of the velocity of the particle. Express your answer in meters per second. | ΑΣφ ? m/s Submit Request Answer Part C Calculate the y-component of the velocity of the particle. Express your answer in meters per second. | ΑΣφ ? m/s Submit Request Answer Part D...
Part B A particle with charge – 5.80 nC is moving in a uniform magnetic field B= -( 1.30 T )k. The magnetic force on the particle is measured to be F=-( 4.00x10-7 N )i+( 7.60x10-7N)j. Calculate the x-component of the velocity of the particle. EVO AO R O P ? Submit Request Answer Part C Calculate the y-component of the velocity of the particle. VALD * o ? Part D A particle with charge – 5.80 nC is moving...
Constants A particle with charge 5.60 nC is moving in a uniform magnetic field B(1.27 T)k, The magnetic force on the particle is measured to be F = -(4.00x10-7 N )? + ( 7.60x10o-7 N. Part A Are there components of the velocity that are not determined by the measurement of the force? yes no Previous Answers Submit Correct Part B Calculate the x-component of the velocity of the particle. Πνα ΑΣφ ? Part B Calculate the x-component of the...
A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24 T )k. The magnetic force on the particle is measured to be F = -(3.00x10-7N)+(7.60x10-7N) Part B Calculate the x-component of the velocity of the particle. I ALP * O a ? V2 = Submit Request Answer Part C Calculate the y-component of the velocity of the particle. IVO AQ o ? ปี Submit Request Answer A particle with charge – 5.20 nC is...
Thank you Exercise 27.8 A particle with charge 6.00 nC is moving in a uniform magnetic field B I.30 T )k. The magnetic force on the particle is measured to be F 3.80x 10-7 N i (7.60 x 10-7 N)j.
A particle with a charge of q = -5.68nC is moving in a uniform magnetic field of B? =( 2.20T ) z^. The magnetic force on the particle is measured to beF? =( 6.10?N )?y^. a) Calculate the x component of the velocity of the particle. b)What is the radius of the circular motion the particle will have in the magnetic field if the particle has a mass of 0.700g ? c)What is the period of this circular motion? d)What...
Part A. Considering light at the two ends of the visible light spectrum, violet light has a _____ wavelength and a _____ photon energy than red light. A.Shorter, higher B.Longer, higher C. Longer, lower D. Shorter, lower Part B. Lenz’s law states that an induced magnetic field in a conductor A. Opposes the change in flux through the conductor. B. Opposes the applied magnetic field. C. Induces a matching electric field...