A particle with charge − 5.40 nC is moving in a uniform magnetic field B⃗ =−( 1.28 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^. |
Part A Part complete Are there components of the velocity that are not determined by the measurement of the force? Are there components of the velocity that are not determined by the measurement of the force?
SubmitPrevious Answers Correct Part B Calculate the x-component of the velocity of the particle.
SubmitRequest Answer Part C Calculate the y-component of the velocity of the particle.
SubmitRequest Answer Part D Calculate the scalar product v⃗ ⋅F⃗ .
SubmitRequest Answer Part E What is the angle between v⃗ and F⃗ ? Give your answer in degrees.
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A particle with charge − 5.40 nC is moving in a uniform magnetic field B⃗ =−(...
A particle with charge − 5.60 nC is moving in a uniform magnetic field B⃗ =−( 1.26 T )k^. The magnetic force on the particle is measured to be F⃗ =−( 4.00×10−7 N )i^+( 7.60×10−7 N )j^. Calculate the scalar product v⃗ ⋅F⃗ .
A particle with a charge of q = -5.60 nC is moving in a uniform magnetic field of B⃗ =( -1.23 T ) k^. The magnetic force on the particle is measured to be F⃗ =( −7.60×10−7 N )j^. Part B Calculate vx, the x component of the velocity of the particle. Express your answer in meters per second. m/s
Constants A particle with charge 5.60 nC is moving in a uniform magnetic field B(1.27 T)k, The magnetic force on the particle is measured to be F = -(4.00x10-7 N )? + ( 7.60x10o-7 N. Part A Are there components of the velocity that are not determined by the measurement of the force? yes no Previous Answers Submit Correct Part B Calculate the x-component of the velocity of the particle. Πνα ΑΣφ ? Part B Calculate the x-component of the...
A particle with charge - 5.00 nC is moving in a uniform magnetic field B=-(1.24 T ). The magnetic force on the particle is measured to be =-(3.80-10-7N)2+(7.60-10-7N)). Part B Calculate the 1-component of the velocity of the particle. Express your answer in meters per second. | ΑΣφ ? m/s Submit Request Answer Part C Calculate the y-component of the velocity of the particle. Express your answer in meters per second. | ΑΣφ ? m/s Submit Request Answer Part D...
A particle with a charge of q = -5.20 nC is moving in a uniform magnetic field of B with sole component B, = -1.28 T. The magnetic force on the particle is measured to be F with sole component Fy = -7.60x10-7 N Calculate Vz, the x component of the velocity of the particle. Express your answer in meters per second. View Available Hint(s) ΡπΙ ΑΣφ ? v_v_x = 144.2 m/s Submit Previous Answers X Incorrect; Try Again; 3...
Part B A particle with charge – 5.80 nC is moving in a uniform magnetic field B= -( 1.30 T )k. The magnetic force on the particle is measured to be F=-( 4.00x10-7 N )i+( 7.60x10-7N)j. Calculate the x-component of the velocity of the particle. EVO AO R O P ? Submit Request Answer Part C Calculate the y-component of the velocity of the particle. VALD * o ? Part D A particle with charge – 5.80 nC is moving...
Figure 1 of 1 Part A Determine the direction of B⃗ for (a) in the figure, where F⃗ represents the maximum magnetic force on a positively charged particle moving with velocity v⃗ . (Figure 1) Determine the direction of for (a) in the figure, where represents the maximum magnetic force on a positively charged particle moving with velocity . left right upward downward inward into the paper outward to the paper SubmitRequest Answer Part B Determine the direction of B⃗ for (b). Determine the direction...
Constante Periodic Table A particle with a charge ol - 5.40 1C is moving in a uniform magnetic field of B = - 1.25 T The magnetic force on the particle is measured to be --(3.00x10-'N ) + ( 7.60x10-N). Part A Are there components of the velocity that cannot be determined by measuring the forca? View Available Hint(s) yes no O Submit Part B Calculate the component of the velocity of the particle. Express your answer in meters per...
A particle with charge – 5.20 nC is moving in a uniform magnetic field B= -(1.24 T )k. The magnetic force on the particle is measured to be F = -(3.00x10-7N)+(7.60x10-7N) Part B Calculate the x-component of the velocity of the particle. I ALP * O a ? V2 = Submit Request Answer Part C Calculate the y-component of the velocity of the particle. IVO AQ o ? ปี Submit Request Answer A particle with charge – 5.20 nC is...
A proton moving in a uniform magnetic field with v⃗ 1=1.13×106ı^m/s experiences force F⃗ 1=1.70×10−16k^N. A second proton with v⃗ 2=2.06×106ȷ^m/s experiences F⃗ 2=−4.17×10−16k^N in the same field. What is the magnitude of B⃗ ? What is the direction of B⃗ ? Give your answer as an angle measured ccw from the +x-axis.