Question

def find astrological sign(month, date): (int, int)-str Given two int values represent ing a month and a date, return a 3-character string that gives us what star sign a person born in that month and on that date belongs to, Use the SIGNS string (already defined for you at the top of this file) to figure this out. NOTE FROM BOB: A lot of string slicing to do here. It looks like the informat ion for each sign is exactly 16 characters Iong e can probably use that >>find astrological sign (8, 24) VIR >find.astrological sign (1, 15) CAP

Python help it is a grade 12 course

Answer 1

Code

SIGNS='03,21-04,17=ARI;04,20-05,20=TAU;05,21-06,21=GEM;06,22-07,22=CAN;07,23-08,22=LEO;08,23-09,22=VIR;09,23-10,23=LIB;10,24-11,20=SCO;11,21-12,21=SAG;12,22-01,20=CAP;01,21-02,21=AQU;02,22-03,20=PIS'

def find_astrological_sign(month,date):

dates=SIGNS.split(";")#split the sign with ; delimeter

for d in dates:
#fetching the starting month from the string
strtMonth=d[:d.find(",")]
d=d[d.find(",")+1:]
#fetching the starting date from the string
startDate=d[:d.find("-")]
d=d[d.find("-")+1:]
#fetching the ending month from the string
endMonth=d[:d.find(",")]
d=d[d.find(",")+1:]
#fetching the ending date from the string
endDate=d[:d.find("=")]
d=d[d.find("=")+1:]
#fetching the sign
sign=d

if(month==int(strtMonth)):
if(date>=int(startDate)):
return sign
if(month==int(endMonth)):
if(date<=int(startDate)):
return sign

print("For the month 8th and date 2 astrology sign is: ",find_astrological_sign(8,24))
print("For the month 1st and date 15 astrology sign is: ",find_astrological_sign(1,15))

output

snap of code for indent

If you have any query regarding the code please ask me in the comment i am here for help you. Please do not direct thumbs down just ask if you have any query. And if you like my work then please appreciates with up vote. Thank You.