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QUESTION 1: PART A. Multiple Choice: In an effort to project toilet paper needs, city mayors ask representative households to

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Answer #1

A)

Here we are using a pairwise manner

For 4 cities

So for each city, we have pair so for 4 cities we have 6 pairs

So each time we have alpha = 0.05

So alpha we are 0.05^6

But in ANOVA the alpha would not change, it Wii same for all pairs.

Which would be 0.05

Answer:- 0.05

B) F 2,57 = 5.25

Number of subjects are equal accross the groups

In F value 2 is k-1 =2. K= 3 is number of treatment

57 = n-k is error degree of freedom

n-3= 57

n = 60

Total 60 subjects. & 3 groups.

60 equally distributed in each group

So 60/3 = 20

Answer:- 20

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