A)
Here we are using a pairwise manner
For 4 cities
So for each city, we have pair so for 4 cities we have 6 pairs
So each time we have alpha = 0.05
So alpha we are 0.05^6
But in ANOVA the alpha would not change, it Wii same for all pairs.
Which would be 0.05
Answer:- 0.05
B) F 2,57 = 5.25
Number of subjects are equal accross the groups
In F value 2 is k-1 =2. K= 3 is number of treatment
57 = n-k is error degree of freedom
n-3= 57
n = 60
Total 60 subjects. & 3 groups.
60 equally distributed in each group
So 60/3 = 20
Answer:- 20
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