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All changes saved A Point of Release Equilibrium Position - Equilibrium- Position Point of A sphere of mass mi, which is attaAll changes saved A Point of Release Equilib Position Equilibrium- Position Point of Release A sphere of mass mi, which is at

A block attached to the lower end of a vertical spring oscillates up and down. If the spring All changes 3. obeys Hookes law      R2 = 2000 R, = 2500 Ry = 6000 -W/ E = 12 V What is the current I? a. 0.8 mA b. 1.0 mA c. 2.0 mA d. 3.0 mA e. 6.0 mA

R= 2000 0 R = 2500 0 Р Lw 8. 14 R, = 6000 п | €= 12V How do the currents 11, 12, and 13 compare? а. І, > 1, > 1, ъ. І, > 1 >Two fire trucks have sirens that emit waves of the same frequency. As the fire trucks approach a person, the person hears a h11. 20.3.1. For which combination for the length L and radius R of a wire will the resistance have the smalle value? O L = 0.13. 20.8.2. A circuit is formed using a battery, three identical resistors, and connecting wires as show does the current pas14. 20.8.3. What is the approximate equivalent resistance of the five resistors shown in the circuit? S 2 First add the 5 ohmAll changes saved A 15. 20.10.2. What is the current through the 1-2 resistor in this circuit? 222 WA 9V S10 ooooo 16. 17.5.4

12. 20.6.1. Consider the circuit shown in the drawing. Two identical light bulbs, labeled A and B, are connected in series wiThe frequencies of the first two overtones (second and third harmonics) of a vibrating 5. string are fand 3f/2. What is the fA simple pendulum and a mass hanging on a spring both have a period of 1 s when set into small oscillatory motion on Earth. T

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Answer #1

as per HOMEWORKLIB RULES I'm only supposed to answer for the first question if you want answers for rest post them separately

1.both masses will have maximum kinetic energy at equilibrium and maximum potential energy at extremes and total energies are constant everywhere

so a is true)

2. im also doing the second one

if time periods are same the angular

angular frequencies will be of the same

so square root(k/m1)= square root(g/l)

so k/m1 =g/l

k=m1g/l

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