a 2kg mass attached to a spring of k = 32 N/m is free to oscillate on a horizontal frictionless surface. the mass is displaced 8 cm to the the right of its equilibrium and set into motion with a leftward push of speed 40 cm/s
c) now consider a simple pendulum that undergoes half as many oscillations per unit time as this mass. the pendulum is released from rest at position 1 and oscillates between position 1 and 3. determine the length of the pendulum, as well as the time required for the pendulum to reach position 2 on its second pass after the initial release.
NOTE:
i think the correct answer is L=2.45 m and t=2.36 s but can you explain why
How do I use the info I know about the mass-spring system and apply it to the pendulum?
Homework Answers
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