Question

A simple random sample from a population with a normal distribution of 104 body temperatures has x-98 70 E and s-065 E Construct estimate of the standard deviation of body temperature of all healthy humans 90% о sden e interval Click the icon to view the table of Chi-Square critical values Round to two decimal places as needed)

Answer 1

We know, $\frac{(n-1)s^2}{\sigma^2}$ ~ $\chi^2_{n-1}$

The 90% confidence interval of population standard deviation is:

[$\sqrt{\frac{(n-1)s^2}{\chi^2_{0.95,n-1}}}$, $\sqrt{\frac{(n-1)s^2}{\chi^2_{0.05,n-1}}}$ ], where, n = 104, s = 0.65

= [0.5838 °F, 0.7349 °F]. (Ans).