A simple random sample from a population with a normal distribution of 97 body temperatures has x overbarequals99.10degrees Upper F and sequals0.68degrees Upper F. Construct an 80% confidence interval estimate of the standard deviation of body temperature of all healthy humans. LOADING... Click the icon to view the table of Chi-Square critical values. nothingdegrees Upper Fless thansigmaless than nothingdegrees Upper F
df = n - 1 = 97 - 1 = 96
Chi square critical values at 0.20 degrees of freedom with 96 df = L = 78.725 ,U = 114.131
80% confidence interval for is
Sqrt ( (n-1) S2 / U) < < Sqrt ( (n-1) S2 / L)
Sqrt [ 96 * 0.682 / 114.131 ) < < Sqrt [ 96 * 0.682 / 78.725 )
0.6237 < < 0.7509
A simple random sample from a population with a normal distribution of 97 body temperatures has...
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